document.write( "Question 762287: Find the lowest degree polynomial f(x) that match the graph below. Leave your answer in factored form.\r
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Algebra.Com's Answer #463835 by jim_thompson5910(35256)\"\" \"About 
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There are 3 roots, and the roots on the very left and very right are double roots (since they only touch the x axis and does not pass through)\r
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\n" ); document.write( "\n" ); document.write( "So there are really 2+1+2 = 5 roots total (2 of which are repeating, only one is a non-repeating root)\r
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\n" ); document.write( "\n" ); document.write( "So the lowest possible degree is a 5th degree polynomial.\r
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\n" ); document.write( "\n" ); document.write( "The roots are: -6, 2, 5\r
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\n" ); document.write( "\n" ); document.write( "The factors would then be: x - (-6), x-2, x-5 which turn into: x-6, x-2, x-5\r
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\n" ); document.write( "\n" ); document.write( "But remember -6 and 5 are double roots, so the factors are really (x-6)^2, (x-2), (x-5)^2\r
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\n" ); document.write( "\n" ); document.write( "Put this all together to get (x-6)^2 * (x-2) * (x-5)^2\r
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\n" ); document.write( "\n" ); document.write( "Then stick a constant k out front to get: k*(x-6)^2 * (x-2) * (x-5)^2\r
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\n" ); document.write( "\n" ); document.write( "Because f(0) = 4, we know that \r
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\n" ); document.write( "\n" ); document.write( "f(x) = k*(x-6)^2 * (x-2) * (x-5)^2\r
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\n" ); document.write( "\n" ); document.write( "f(0) = k*(0-6)^2 * (0-2) * (0-5)^2\r
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\n" ); document.write( "\n" ); document.write( "4 = k*(0-6)^2 * (0-2) * (0-5)^2\r
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\n" ); document.write( "\n" ); document.write( "Now solve for k
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