document.write( "Question 762284: I was wondering for equation,sqrt(3y+7)= y+1, y =-2&3
\n" ); document.write( "-2 because you would get sqrt(3(-2)+7)=-2+1 ==>sqrt (1)=-1, and this works because sqrt 1= -1^2
\n" ); document.write( "So would -2 be one of the solutions?
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Algebra.Com's Answer #463831 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"sqrt%283y%2B7%29=+y%2B1\"....square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%283y%2B7%29%29%5E2=+%28y%2B1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"3y%2B7=+y%5E2%2B2y%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"0=+y%5E2-3y%2B2y%2B1-7\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2B2y-3y-6=0\".....group to factor\r
\n" ); document.write( "\n" ); document.write( "\"%28y%5E2%2B2y%29-%283y-6%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"y%28y%2B2%29-3%28y-2%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-3%29%28y%2B2%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28y-3%29+=+0\" => \"y=3\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28y%2B2%29+=+0\" => \"y=-2\"\r
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