document.write( "Question 762139: Please help me solve:In a birthday party,out of 53 children,8 children have neither an ice cream not a cold drink.If 30 children have ice cream and 23 children have cold drink,find:
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\n" ); document.write( "ii]how many children have only cold drinks
\n" ); document.write( "iii]how many children have both cold drinks and ice cream\r
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Algebra.Com's Answer #463775 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Total children: 53\r
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\n" ); document.write( "\n" ); document.write( "Children that had neither: 8\r
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\n" ); document.write( "\n" ); document.write( "Children that had something: 53 - 8 = 45\r
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\n" ); document.write( "\n" ); document.write( "Children that had ice cream plus children that had cold drinks = 30 + 23 = 53.\r
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\n" ); document.write( "\n" ); document.write( "53 is 8 more than 45, so 8 of the children must have been counted twice when adding the 30 plus the 23. Hence, 8 had both. If 30 had ice cream and 8 had both, then 30 minus 8 = 22 had ice cream only. If 23 had cold drinks and 8 had both, then 23 minus 8 = 15 had cold drinks only.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "22 ice cream only\r
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\n" ); document.write( "\n" ); document.write( "15 cold drink only\r
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\n" ); document.write( "\n" ); document.write( "8 both\r
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\n" ); document.write( "\n" ); document.write( "8 nothing\r
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\n" ); document.write( "\n" ); document.write( "22 + 15 + 8 + 8 = 53\r
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\n" ); document.write( "Egw to Beta kai to Sigma
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