document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762125>Question 762125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum to infinity of the Geometric progression with first term 3 and common ratio 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463720 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 'a' is the first term, and 'r' the common ratio of the GP,<BR>\n" );
document.write( "the sum to infinity is given by the formula  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S+=+a%2F%281-r%29 ALIGN=MIDDLE  ALT=\"S+=+a%2F%281-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Here, a = 3 and r = 1/2\r<BR>\n" );
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document.write( "Substitute in the above equation and you get S as 6.\r<BR>\n" );
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document.write( "Got it?\r<BR>\n" );
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document.write( "Pl check out solved problem 761611 also.\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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