document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762122>Question 762122</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A MIXTURE OF 40 LITRES CONTAINS 10% WATER AND 90% MILK.  HOW MANY LITRES OF WATER IS TO BE ADDED TO MAKE THE WATER CONTENT 20% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463715 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A MIXTURE OF 40 LITRES CONTAINS 10% WATER AND 90% MILK. HOW MANY LITRES OF WATER IS TO BE ADDED TO MAKE THE WATER CONTENT 20%<BR>\n" );
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document.write( "let x=amount of water to add.<BR>\n" );
document.write( "10%*40=4 litres=amount of water in original mixture<BR>\n" );
document.write( "4+x=amount of water in new mixture<BR>\n" );
document.write( "40+x=amount of new mixture<BR>\n" );
document.write( "4+x=20%(40+x)<BR>\n" );
document.write( "4+x=8+0.2x<BR>\n" );
document.write( "0.8x=4<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "amount of water to add=5 litres </SPAN>\n" );
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