document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762101>Question 762101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ratio of age of x and y is 5:6 after 5 years it will 3:2.find the present?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463703 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ratio of age of x and y is 5:6 after 5 years it will 3:2.find the present??<BR>\n" );
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document.write( "x/y = 5/6 --> x = 5y/6<BR>\n" );
document.write( "(x+5)/(y+5) = 3/2 --> 3y+15 = 2x+10<BR>\n" );
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document.write( "3y+15 = 2x+10<BR>\n" );
document.write( "sub for x<BR>\n" );
document.write( "3y + 15 = 2(5y/6) + 10<BR>\n" );
document.write( "9y + 45 = 5y + 30<BR>\n" );
document.write( "4y = -15<BR>\n" );
document.write( "y = -3.75<BR>\n" );
document.write( "x = -3.125<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "The problem is that x was younger, then 5 years later x was older.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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