document.write( "Question 762066: Given a polynomial and one of its factors, find the remaining factors of the polynomial. Some of the factors may not be binomials.\r
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Algebra.Com's Answer #463684 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I think this problem was botched. The other tutor's answer in incorrect because\r\n" );
document.write( "you don't have a factor if the remainder isn't 0. And certainly a remainder of\r\n" );
document.write( "100 is not a remainder of 0. \r\n" );
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document.write( "I had to change your last term +8 to +108, because otherwise none of those,\r\n" );
document.write( "not even x-12, would have been factors. So I assumed the last term should have\r\n" );
document.write( "been +108, not +8.\r\n" );
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document.write( "64x³-768x²-9x+108; x-12 \r\n" );
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document.write( "12|64 -768 -9  108\r\n" );
document.write( "  |    768  0 -108\r\n" );
document.write( "   64    0 -9    0\r\n" );
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document.write( "So 64x³-768x²-9x+108 factors as  \r\n" );
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document.write( "(x-12)(64x²-9)\r\n" );
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document.write( "Then 64x²-9 factors as (8x-3)(8x+3)\r\n" );
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document.write( "So the complete factorization is\r\n" );
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document.write( "(x-12)(8x-3)(8x+3)\r\n" );
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document.write( "So all 7 factors are:\r\n" );
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document.write( "1.  1\r\n" );
document.write( "2.  x-12 \r\n" );
document.write( "3.  8x-3 \r\n" );
document.write( "4.  8x+3 \r\n" );
document.write( "5.  (x-12)(8x-3) = 8x²-99x+36 \r\n" );
document.write( "6.  (x-12)(8x+3) = 8x²-93x-36\r\n" );
document.write( "7.  (8x-3)(8x+3) = 64x²-9 \r\n" );
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document.write( "On your list, A, B, and C are factors, but D is not a factor. \r\n" );
document.write( "(Incidentally, B and C are the same.)\r\n" );
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document.write( "Edwin
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