document.write( "Question 762070: y+3=-1/2(x-2)^2 how to graph the parabola \n" ); document.write( "
Algebra.Com's Answer #463677 by stanbon(75887)\"\" \"About 
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y+3=-1/2(x-2)^2 how to graph the parabola\r
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\n" ); document.write( "The equation is in vertex form:
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\n" ); document.write( "Vertex is at (2,-3)
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\n" ); document.write( "The form indicates the parabola is opening downward because of the \"-1/2\"
\n" ); document.write( "coefficient in the x^2 term.
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\n" ); document.write( "The y-intercept is (0,-5)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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