document.write( "Question 762070: y+3=-1/2(x-2)^2 how to graph the parabola \n" ); document.write( "
Algebra.Com's Answer #463677 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y+3=-1/2(x-2)^2 how to graph the parabola\r \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "The equation is in vertex form: \n" ); document.write( "---- \n" ); document.write( "Vertex is at (2,-3) \n" ); document.write( "----- \n" ); document.write( "The form indicates the parabola is opening downward because of the \"-1/2\" \n" ); document.write( "coefficient in the x^2 term. \n" ); document.write( "---- \n" ); document.write( "The y-intercept is (0,-5) \n" ); document.write( "=============================== \n" ); document.write( " \n" ); document.write( "---------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |