document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760047>Question 760047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 3x + (y-2)i = (5-2x) + (3y-8)i, then (x, y) is?<BR>\n" );
document.write( "Another one: If (x + iy)2 = 3+4i, then (x, y) is?\r<BR>\n" );
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document.write( "How am I supposed to proceed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463624 by </B><A HREF=/tutors/aboutme.mpl?userid=blueplanet><B>blueplanet(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blueplanet><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blueplanet><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Both equations can be solved by equating their real parts and by equating their imaginary parts.\r<BR>\n" );
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document.write( "To solve 3x + (y-2)i = (5-2x) + (3y-8)i,  we can approach the problem by equating the real parts first:\r<BR>\n" );
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document.write( "3x = 5-2x<BR>\n" );
document.write( "=> x=1\r<BR>\n" );
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document.write( "Then, equating the imaginary parts, we get:\r<BR>\n" );
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document.write( "y-2 = 3y-8<BR>\n" );
document.write( "y = 3\r<BR>\n" );
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document.write( "So, (x,y) = (1,3).\r<BR>\n" );
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document.write( "You can use a similar approach to resolve (x + iy)2 = 3+4i. If my calculation is correct, the answer should be (x,y) = (3/2, 2).<BR>\n" );
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