document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761976>Question 761976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A crew can row 6000 yards up stream in the same time it takes them to cover 8000 yards downstream.  If the speed of the current is 80 yards per minute find the speed the crew can row in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463621 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the speed the crew can row in still water=x yards per minute say<BR>\n" );
document.write( "the speed of the current is 80 yards per minute<BR>\n" );
document.write( "the speed in down stream= x+80 & the distance traveled is 8000 yards<BR>\n" );
document.write( "so time taken=8000/(x+80)<BR>\n" );
document.write( "& in up stream=x-80 & the distance traveled is 6000 yards<BR>\n" );
document.write( "so time taken=6000/(x-80)<BR>\n" );
document.write( "the crew can row 6000 yards up stream in the same time it takes them to cover 8000 yards downstream. <BR>\n" );
document.write( "so 8000/(x+80)=6000/(x-80)<BR>\n" );
document.write( "or 4(x-80)=3(x+80)<BR>\n" );
document.write( "or 4x-320=3x+240<BR>\n" );
document.write( "or x=320+240=560 <BR>\n" );
document.write( "so the speed the crew can row in still water=560 yards per minute say </SPAN>\n" );
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