document.write( "Question 761962: Please help me on this problem: Suppose \"k\" is some positive interger. Consider numbers of the form √n) where \"n\" is a positive interger. In terms of \"k,\" how many numbers of this form differ from \"k\" bh less than 1? Explain why your answer works in general. (Hint: for this question it may help to try some small values of \"k\" and search for a pattern in the results. For example, if k= 2 there are 7 numbers of the desired form that differ from \"k\" by less than one since √2), √3), √4), √5), √6), √7), and √8) are the only such numbers that differ from 2 by less than 1. Now, try k=3 and so forth. After you find a formula think about why your formula works in general.) \n" ); document.write( "
Algebra.Com's Answer #463615 by ramkikk66(644)![]() ![]() ![]() You can put this solution on YOUR website! For any number k,\r \n" ); document.write( "\n" ); document.write( "all values of n in the range (k-1)^2 and (k+1)^2 will satisfy the condition, where sqrt(n) would differ from k by less than 1.\r \n" ); document.write( "\n" ); document.write( "How many numbers are there between k^2 and (k+1)^2?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How many numbers are there between k^2 and (k-1)^2?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sum of the two = \n" ); document.write( "\n" ); document.write( "However, this list of 4k numbers also includes k twice. So we have to reduce it by 1.\r \n" ); document.write( "\n" ); document.write( "So, total possible values of n where sqrt(n) differs from k by less than 1,\r \n" ); document.write( "\n" ); document.write( "is \n" ); document.write( "\n" ); document.write( ":)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check a few samples: \n" ); document.write( "For k = 2, the set of n would be sqrt(2) to sqrt(8) = 7 numbers = 4*2 - 1 \n" ); document.write( "For k = 3, the set of n would be sqrt(5) to sqrt(15) = 11 numbers = 4*3 - 1 \n" ); document.write( "For k = 5, the set of n would be sqrt(17) to sqrt(35) = 19 numbers = 4*5 - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |