document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761960>Question 761960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a lot is in the shape of a right triangle. the hypotenuse is 3m longer than the longer leg. the longer leg is 6m longer than twice the length of the shorter leg. find the lengths of the sides of the lot. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463613 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Shorter leg = x<BR>\n" );
document.write( "Longer leg = 6 + 2x<BR>\n" );
document.write( "Hypotenuse = 9 + 2x<BR>\n" );
document.write( "(6 + 2x)^2 + x^2 = (9 + 2x)^2<BR>\n" );
document.write( "36 + 24x + 4x^2 + x^2 = 81 + 36x + 4x^2<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "x^2 - 12x - 45 = 0<BR>\n" );
document.write( "(x + 3)(x - 15) = 0<BR>\n" );
document.write( "x = -3 (No answer)<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "Shorter leg = 15m<BR>\n" );
document.write( "Longer leg = 36m<BR>\n" );
document.write( "Hypotenuse = 39m<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "15^2 + 36^2 = 39^2<BR>\n" );
document.write( "      1521m = 1521m<BR>\n" );
document.write( "hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );