document.write( "Question 761898: the ratio of the base of an isosceles triangle to its altitude is 3:4. find the measures of the angles pf the triangle. \n" ); document.write( "
Algebra.Com's Answer #463570 by josgarithmetic(39620)\"\" \"About 
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Much like saying ratio of base to altitude is 6:8. The altitude cuts this isosceles triangle into two right-triangles, each with legs in the ratio of 3:8. The hypotenuse would then have corresponding value of h, related as \"h=sqrt%283%5E2%2B8%5E2%29=sqrt%289%2B64%29=highlight%28sqrt%2873%29=h%29\"\r
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\n" ); document.write( "\n" ); document.write( "Each of the angles at the endpoints of the original isosceles triangle measure as \"arcsin%288%2Fsqrt%2873%29%29\" degrees (about 69.4 degrees).\r
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\n" ); document.write( "\n" ); document.write( "The angle at top from where the altitude is drawn will be \"180-2%2Aarcsin%288%2Fsqrt%2873%29%29\" degrees.\r
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