document.write( "Question 761829: 2 cities are 1980 miles apart. one trip flying into the wind took 5.5 hours, the return trip with the wind took only 4.5 hours. what is the speed of the wind and the plane in still air \n" ); document.write( "
Algebra.Com's Answer #463568 by ramkikk66(644) ![]() You can put this solution on YOUR website! Let x be the speed of plane in still air and y be the wind speed.\r \n" ); document.write( "\n" ); document.write( "Step 1: Flying into the wind, effective speed = \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 2: Flying with the wind - effective speed = \n" ); document.write( "Applying the same formula distance = speed * time\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 3: \n" ); document.write( "From eqn 1, x = y + 360. Substituting for x in eqn 2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 4: \n" ); document.write( "Since y = 40, \n" ); document.write( "\n" ); document.write( "Speed of plane in still air = \n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( " \n" ); document.write( " |