document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761892>Question 761892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee shop is mixing Arabic coffee worth $15.00 per pound with Brazilian coffee worth $22.00 per pound. The combination will sell for $20.00 per pound. To make 100 Pounds of this mixture, how much of each type of coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463563 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Step 1: In the combination of 100 pounds, let there be x pounds of Arabic.<BR>\n" );
document.write( "Step 2: So, the combination has (100 - x) pounds of Brazilian<BR>\n" );
document.write( "Step 3: Cost of the mixture = cost of arabic in mix + cost of brazilian in mix\r<BR>\n" );
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document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2815%2Ax+%2B+22%2A%28100-x%29%29 ALIGN=MIDDLE  ALT=\"%2815%2Ax+%2B+22%2A%28100-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Step 4: But the cost of the mixture is given to be 20 per pound. Or, cost of 100 pounds of mix = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2A100+=+2000 ALIGN=MIDDLE  ALT=\"20%2A100+=+2000\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 5: The values of step 3 and step 4 have to be equal. Hence we have the equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2815%2Ax+%2B+22%28100+-+x%29%29+=+2000 ALIGN=MIDDLE  ALT=\"%2815%2Ax+%2B+22%28100+-+x%29%29+=+2000\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 6: Solve for x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2Ax+%2B+2200+-+22%2Ax+=+2000 ALIGN=MIDDLE  ALT=\"15%2Ax+%2B+2200+-+22%2Ax+=+2000\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=200+=+7%2Ax ALIGN=MIDDLE  ALT=\"200+=+7%2Ax\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+200%2F7 ALIGN=MIDDLE  ALT=\"x+=+200%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the mixture has <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=200%2F7 ALIGN=MIDDLE  ALT=\"200%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > pounds of Arabic and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100+-+200%2F7+=500%2F7 ALIGN=MIDDLE  ALT=\"100+-+200%2F7+=500%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > pounds of Brazilian coffee.\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );