document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761823>Question 761823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An eastbound train and a westbound train meet each other on parallel tracks heading in opposite directions. The eastbound train travels 16 miles per hour faster than the westbound train. After 2.5 hours, they are 320 miles apart. At what speeds are the two trains traveling?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463554 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Step 1: Let speed of westbound train be x miles per hour<BR>\n" );
document.write( "Step 2: Then speed of eastbound train is (x+16) miles per hour\r<BR>\n" );
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document.write( "Step 3: So, at the end of every hour, the distance between them would be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+x+%2B+16+=+2%2Ax%2B16 ALIGN=MIDDLE  ALT=\"x+%2B+x+%2B+16+=+2%2Ax%2B16\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles, since they are travelling in opposite directions\r<BR>\n" );
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document.write( "Step 4: At the end of 2.5 hours, the distance would be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.5%2A%282%2Ax%2B16%29+=+5%2Ax+%2B+40 ALIGN=MIDDLE  ALT=\"2.5%2A%282%2Ax%2B16%29+=+5%2Ax+%2B+40\"   DISABLED_style= \"max-width:90%; height:auto;\" >   ---> multiplying step 3 by 2.5\r<BR>\n" );
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document.write( "Step 5: Since the distance between them is given to be 320 miles after 2.5 hours, we equate the result of step 4 to 320.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2Ax+%2B+40+=+320 ALIGN=MIDDLE  ALT=\"5%2Ax+%2B+40+=+320\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 6: Solve for x. Subtract 40 from both sides, and divide by 5.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2Ax+=+280 ALIGN=MIDDLE  ALT=\"5%2Ax+=+280\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+280%2F5+=+56 ALIGN=MIDDLE  ALT=\"x+=+280%2F5+=+56\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Speed of westbound train is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%2856%29 ALIGN=MIDDLE  ALT=\"highlight%2856%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and speed of eastbound train is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=56%2B16=highlight%2872%29 ALIGN=MIDDLE  ALT=\"56%2B16=highlight%2872%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles per hour.\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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