document.write( "Question 761807: If a new rectangle has three times the length and width of the original rectangle, how would the perimeters and areas compare? \n" ); document.write( "
Algebra.Com's Answer #463538 by josgarithmetic(39626)\"\" \"About 
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Try just using variables for length and width.\r
\n" ); document.write( "\n" ); document.write( "y=length and w=width.
\n" ); document.write( "Original rectangle, perimeter = 2y+2w.\r
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\n" ); document.write( "\n" ); document.write( "New rectangle according to 3y and 3w.
\n" ); document.write( "New perimeter = 2*3y+2*3w.\r
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\n" ); document.write( "\n" ); document.write( "How do these compare?
\n" ); document.write( "New perimeter divided by original perimeter=
\n" ); document.write( "\"2%2A3%2A%28y%2Bw%29%2F%282%28y%2Bw%29%29=3%2A%28y%2Bw%29%2F%28y%2Bw%29=3\"
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