document.write( "Question 761807: If a new rectangle has three times the length and width of the original rectangle, how would the perimeters and areas compare? \n" ); document.write( "
Algebra.Com's Answer #463538 by josgarithmetic(39626) ![]() You can put this solution on YOUR website! Try just using variables for length and width.\r \n" ); document.write( "\n" ); document.write( "y=length and w=width. \n" ); document.write( "Original rectangle, perimeter = 2y+2w.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "New rectangle according to 3y and 3w. \n" ); document.write( "New perimeter = 2*3y+2*3w.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How do these compare? \n" ); document.write( "New perimeter divided by original perimeter= \n" ); document.write( " |