document.write( "Question 761850: After making a trip of 126 miles, a lady found that if she had increased her average speed by 8mph, she could have made the trip in 1 hour less time. Find her original speed.\r
\n" ); document.write( "\n" ); document.write( "My 2 equations:
\n" ); document.write( "original: 126=(s+8)*(t-1)
\n" ); document.write( "theoretical trip: 126=s*t
\n" ); document.write( "After I plug the 2nd equation into the first I do not know what to do.
\n" ); document.write( "126=(s+8)*((126/s)-1)
\n" ); document.write( "Please help! Thank You Thank You Thank You!!!!! -Abby \n" ); document.write( "
Algebra.Com's Answer #463535 by Alan3354(69443)\"\" \"About 
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After making a trip of 126 miles, a lady found that if she had increased her average speed by 8mph, she could have made the trip in 1 hour less time. Find her original speed.\r
\n" ); document.write( "\n" ); document.write( "My 2 equations:
\n" ); document.write( "original: 126=(s+8)*(t-1)
\n" ); document.write( "theoretical trip: 126=s*t
\n" ); document.write( "After I plug the 2nd equation into the first I do not know what to do.
\n" ); document.write( "126=(s+8)*((126/s)-1)
\n" ); document.write( "------------
\n" ); document.write( "Solve for s
\n" ); document.write( "126 = (s+8)*((126-s/s))
\n" ); document.write( "126s = -s^2 + 118s + 1008
\n" ); document.write( "s^2 + 8s - 1008 = 0
\n" ); document.write( "(s+36)*(s-28) = 0
\n" ); document.write( "s = 28 mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "126/28 = 4.5 hours
\n" ); document.write( "126/36 = 3.5 hours \n" ); document.write( "
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