document.write( "Question 761723: 7sin^2x+cos^2x=4 then cosx= \n" ); document.write( "
Algebra.Com's Answer #463440 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "7sin^2x + cos^2x = 4\r
\n" ); document.write( "\n" ); document.write( "Split the 7 on the left hand side as 6 and 1\r
\n" ); document.write( "\n" ); document.write( "6sin^2x + sin^2x + cos^2x = 4 \r
\n" ); document.write( "\n" ); document.write( "Since sin^2x + cos^2x = 1\r
\n" ); document.write( "\n" ); document.write( "6sin^2x + 1 = 4\r
\n" ); document.write( "\n" ); document.write( "6sin^2x = 3\r
\n" ); document.write( "\n" ); document.write( "sin^2x = 1/2\r
\n" ); document.write( "\n" ); document.write( "sin x = 1/sqrt(2) or -1/sqrt(2)\r
\n" ); document.write( "\n" ); document.write( "Therefore\r
\n" ); document.write( "\n" ); document.write( "cos x = 1/sqrt(2) or -1/sqrt(2) (cos x = sqrt (1 - sin^2x)\r
\n" ); document.write( "\n" ); document.write( ":)
\n" ); document.write( "
\n" );