document.write( "Question 761562: if x/3=y/5=z/7 then (z2-x2+y2)/2y2= \n" ); document.write( "
Algebra.Com's Answer #463436 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
I think you are asking for the value of the expression\r
\n" ); document.write( "\n" ); document.write( "\"%28z%5E2+-+x%5E2+%2B+y%5E2%29%2F%282%2Ay%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "Given that x/3=y/5=z/7\r
\n" ); document.write( "\n" ); document.write( "First, we express x and z in terms of y\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3+=+y%2F5\" Therefore \"x+=+3%2Ay%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"z%2F7+=+y%2F5\" Therefore \"z+=+7%2Ay%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Now in the given expression, substitute for x and z in terms of y\r
\n" ); document.write( "\n" ); document.write( "\"%28z%5E2+-+x%5E2+%2B+y%5E2%29%2F%282%2Ay%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "\"%28%287%2Ay%2F5%29%5E2+-+%283%2Ay%2F5%29%5E2+%2B+y%5E2%29%2F%282%2Ay%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "\"%2849%2Ay%5E2%2F25+-+9%2Ay%5E2%2F25+%2B+y%5E2%29%2F%282%2Ay%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "\"65%2Ay%5E2%2F%2825%2A2%2Ay%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "=\r
\n" ); document.write( "\n" ); document.write( "\"13%2F10\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( ":)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );