document.write( "Question 761707: if a:b=2:3, b:c=4:5, c:d= 6:7 so find a:b:c:d? \n" ); document.write( "
Algebra.Com's Answer #463427 by MathLover1(20849)\"\" \"About 
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A . . . .2 . . . . .B . . . 4 . . . . . C . . . 6
\n" ); document.write( "-- . = . --- . . . . -- . = . -- . . . . . -- .= .----
\n" ); document.write( "B . . . .3 . . . . .C . . . 5 . . . . . D . . . 7\r
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\n" ); document.write( "\n" ); document.write( "The best way I think I can explain this is first to find the LCM of \"3\", \"5\" and \"7\", which, of course, is \"3+%2A+5+%2A+7+=+105\".\r
\n" ); document.write( "\n" ); document.write( "Now express each of the fractions above with a denominator of \"105\".\r
\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "\"A+%2F+B+=+70+%2F+105\"\r
\n" ); document.write( "\n" ); document.write( "\"B+%2F+C+=+84+%2F105\"\r
\n" ); document.write( "\n" ); document.write( "\"C+%2F+D+=+90+%2F+105\" . . . . . . . . . ( 1 )\r
\n" ); document.write( "\n" ); document.write( "In the last ratio, we have \"C\" as \"90\". How can we express \"B+%2F+C\" as \"x+%2F+90\"?\r
\n" ); document.write( "\n" ); document.write( "Well, \r
\n" ); document.write( "\n" ); document.write( "\"B+%2F+C+=+84+%2F+105\", so if we want to express this as\"+x+%2F+90\", then\r
\n" ); document.write( "\n" ); document.write( "\"84+%2F+105+=+x+%2F+90\"\r
\n" ); document.write( "\n" ); document.write( "So \"x+=+84+%2890+%2F+105%29+=+72\"\r
\n" ); document.write( "\n" ); document.write( "Therefore we can express \"B+%2F+C\" as \"72+%2F+90\" . . . . . . . . ( 2 )\r
\n" ); document.write( "\n" ); document.write( "We have that \"A+%2F+B+=+70+%2F+105\", and now we want to get it so that \"B\" is \"72\".\r
\n" ); document.write( "\n" ); document.write( "So \"70+%2F+105+=+y+%2F+72\"\r
\n" ); document.write( "\n" ); document.write( "Hence \"y+=+70+%2872+%2F+105%29+=+48\"\r
\n" ); document.write( "\n" ); document.write( "Therefore we can express \"A+%2F+B\" as \"48+%2F+72\" . . . . . . . . ( 3 )\r
\n" ); document.write( "\n" ); document.write( "Collecting the three ratios ( 1 ), ( 2 ) and ( 3 ) together, we have\r
\n" ); document.write( "\n" ); document.write( "A . . . 48 . . . . . B . . . .72 . . . . . C . . . 90
\n" ); document.write( "-- . = . ---- . . . . --- . = . ---- . . . . . -- .= .-----
\n" ); document.write( "B . . . 72 . . . . . C . . . .90 . . . . . D . . .105\r
\n" ); document.write( "\n" ); document.write( "From which you can see that \"A+%3A+B+%3A+C+%3A+D+=+48+%3A+72+%3A+90+%3A+105\"\r
\n" ); document.write( "\n" ); document.write( "or, dividing by \"3\", you get in lowest terms\r
\n" ); document.write( "\n" ); document.write( "\"A+%3A+B+%3A+C+%3A+D+=+16+%3A+24+%3A+30+%3A+35\"
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