document.write( "Question 761648: Graph the line with slope 3 passing through the point (-2,-2)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #463423 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
A linear equation can be expressed in the form y = mx + c where m is the slope and c is the y intercept (the value of y when x = 0, or the point where the line intersects the y axis)\r
\n" ); document.write( "\n" ); document.write( "Here, we know the slope m(3) and one instance of x and y (-2,-2). We don't know c.\r
\n" ); document.write( "\n" ); document.write( "By substituting for m,x and y we have\r
\n" ); document.write( "\n" ); document.write( "-2 = -2*3 + c\r
\n" ); document.write( "\n" ); document.write( "or \"c+=+4\"\r
\n" ); document.write( "\n" ); document.write( "So the line's equation is \"y+=+3x+%2B+4\" or \"3x+-+y+=+-4\"\r
\n" ); document.write( "\n" ); document.write( "See the graph below.\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"3+x+%2B+-1+y+=+-4\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-3%2F-1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -4/3 = -1.33333333333333.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -4/-1 = 4.
  • Slope is -3/-1 = 3.
  • Equation in slope-intercept form: y=3*x+4.
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );