document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761236>Question 761236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two numbers whose sum is 100 if one number is 16 more than twice the smaller number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463358 by </B><A HREF=/tutors/aboutme.mpl?userid=2897696><B>2897696(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=2897696><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=2897696><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can solve this problem by a method called VEWAS<BR>\n" );
document.write( "V=variable<BR>\n" );
document.write( "E=equation<BR>\n" );
document.write( "W=work (solving equation)<BR>\n" );
document.write( "A=answer<BR>\n" );
document.write( "S=sentence(optional)\r<BR>\n" );
document.write( "\n" );
document.write( "V: let x=smallest number x#2=2x+16<BR>\n" );
document.write( "E: x+2x+16=100<BR>\n" );
document.write( "W: 3x+16=100 (solve for x)<BR>\n" );
document.write( "   3x=84<BR>\n" );
document.write( "   x=28(this is the smallest number) plug the smallest number into the equation in finding x#2 ---> 2(28)+16=56+16-->72<BR>\n" );
document.write( "A: x=28 x#2=72<BR>\n" );
document.write( "S: (optional) the two numbers are 28 and 72. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );