document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761619>Question 761619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man travels 1 mile east , then 5 miles south and then 2 miles east and finally 9 miles north , how far is he from the starting point ? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463352 by </B><A HREF=/tutors/aboutme.mpl?userid=Stitch><B>Stitch(470)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Stitch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem can be solved by adding the vectors together and then drawing a right triangle.<BR>\n" );
document.write( "1 miles East + 2 miles East = 3 miles East<BR>\n" );
document.write( "Since the North distance is larger, we will call North positive.<BR>\n" );
document.write( "9 miles North - 5 miles South = 4 miles North.<BR>\n" );
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document.write( "Now you can use the Pythagorean theorem to find C:\r<BR>\n" );
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document.write( "He is now 5 miles from the starting point.<BR>\n" );
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