document.write( "Question 761558: the width of a rectangle is ten inches less than its length the perimeter of the rectangle is 112 what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #463346 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Length = x \n" ); document.write( "Width = x - 10 \n" ); document.write( "Perimeter = 2* length + 2* width \n" ); document.write( " 112 = 2*x + 2*(x - 10) \n" ); document.write( " 112 = 2x + 2x - 20 \n" ); document.write( " 4x = 112 + 20 \n" ); document.write( " 4x = 132 \n" ); document.write( " x = 33ins \n" ); document.write( "Length = 33ins \n" ); document.write( "Width = 23ins \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |