document.write( "Question 761558: the width of a rectangle is ten inches less than its length the perimeter of the rectangle is 112 what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #463346 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Length = x
\n" ); document.write( "Width = x - 10
\n" ); document.write( "Perimeter = 2* length + 2* width
\n" ); document.write( " 112 = 2*x + 2*(x - 10)
\n" ); document.write( " 112 = 2x + 2x - 20
\n" ); document.write( " 4x = 112 + 20
\n" ); document.write( " 4x = 132
\n" ); document.write( " x = 33ins
\n" ); document.write( "Length = 33ins
\n" ); document.write( "Width = 23ins
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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