document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761595>Question 761595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Indicate in standard form the equation of the line passing through the given points.E(-2, 2), F(5, 1)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463338 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using y2 - y1/x2 - x1 to find the gradient<BR>\n" );
document.write( "      1 - 2/5 -(-2)<BR>\n" );
document.write( "        -1/7<BR>\n" );
document.write( "Using y - b = m(x - a) with F (5,1)<BR>\n" );
document.write( "      y - 1 = -1/7(x - 5)<BR>\n" );
document.write( "      y - 1 = -1/7x + 5/7<BR>\n" );
document.write( "          y = -1/7x + 5/7 + 7/7<BR>\n" );
document.write( "         = y = -1/7x + 12/7<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "         = 7y = -x + 12<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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