document.write( "Question 761563: write an equation of the line that passes through (-2,3) and is perpendicular to the line y=2x+1 \n" ); document.write( "
Algebra.Com's Answer #463333 by ramkikk66(644)\"\" \"About 
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First line is y = 2x + 1 \r
\n" ); document.write( "\n" ); document.write( "It is already of the form y = mx + c where m is the slope.\r
\n" ); document.write( "\n" ); document.write( "So slope of the first line = 2.\r
\n" ); document.write( "\n" ); document.write( "Therefore, slope of the perpendicular line = -1/2\r
\n" ); document.write( "\n" ); document.write( "(product of the slopes of perpendicular lines is -1)\r
\n" ); document.write( "\n" ); document.write( "The second line has slope -1/2 and passes through -2,3\r
\n" ); document.write( "\n" ); document.write( "Let its equation be y = mx + c where we already know m, and we know 1 set of values for x and y, but don't know c.\r
\n" ); document.write( "\n" ); document.write( "So, in the equation for the second line, we can substitute for y, m and x.\r
\n" ); document.write( "\n" ); document.write( "\"3+=+-1%2F2%2A-2+%2B+c\"\r
\n" ); document.write( "\n" ); document.write( "\"3+=+1+%2B+c\" \r
\n" ); document.write( "\n" ); document.write( "Subtracting 1 from either side\r
\n" ); document.write( "\n" ); document.write( "\"c+=+2\"\r
\n" ); document.write( "\n" ); document.write( "So the equation to the second line with m = -1/2, c = 2 is\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-%281%2F2%29x+%2B+2\"\r
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