document.write( "Question 761279: Find the vertex and directrix for the parabola\r
\n" ); document.write( "\n" ); document.write( "y + 2 = 1/3 (x+2) ^ 2
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Algebra.Com's Answer #463305 by lwsshak3(11628)\"\" \"About 
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Find the vertex and directrix for the parabola
\n" ); document.write( "y + 2 = 1/3 (x+2) ^ 2
\n" ); document.write( "rewrite equation in basic form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "\"y%2B2=%281%2F3%29%28x%2B2%29%5E2\"
\n" ); document.write( "\"3y%2B6%29=%28x%2B2%29%5E2\"
\n" ); document.write( "\"%28x%2B2%29%5E2=3%28y%2B2%29\"
\n" ); document.write( "This is an equation of a parabola that opens upward.
\n" ); document.write( "vertex: (-2,-2)
\n" ); document.write( "axis of symmetry: x=-2
\n" ); document.write( "4p=3
\n" ); document.write( "p=3/4
\n" ); document.write( "directrix: y=11/4 (p-units below vertex on the axis of symmetry.\r
\n" ); document.write( "\n" ); document.write( "see graph below as a visual check
\n" ); document.write( "y= (x^2+4x+4)/3-2\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%5E2%2B4x%2B4%29%2F3-2%29+\"
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