document.write( "Question 761279: Find the vertex and directrix for the parabola\r
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document.write( "y + 2 = 1/3 (x+2) ^ 2 \n" );
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Algebra.Com's Answer #463305 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex and directrix for the parabola \n" ); document.write( "y + 2 = 1/3 (x+2) ^ 2 \n" ); document.write( "rewrite equation in basic form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is an equation of a parabola that opens upward. \n" ); document.write( "vertex: (-2,-2) \n" ); document.write( "axis of symmetry: x=-2 \n" ); document.write( "4p=3 \n" ); document.write( "p=3/4 \n" ); document.write( "directrix: y=11/4 (p-units below vertex on the axis of symmetry.\r \n" ); document.write( "\n" ); document.write( "see graph below as a visual check \n" ); document.write( "y= (x^2+4x+4)/3-2\r \n" ); document.write( "\n" ); document.write( " |