document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761245>Question 761245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is 2/5 to the third power </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463262 by </B><A HREF=/tutors/aboutme.mpl?userid=2897696><B>2897696(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=2897696><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=2897696><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know that x^2=x*x, y^7=y*y*y*y*y*y*y,or (y/u)^3=(y/u)*(y/u)*(y/u), so <BR>\n" );
document.write( "(2/5)^3=(2/5)*(2/5)*(2/5).<BR>\n" );
document.write( "now we multiply the numerator  and the denominator together.<BR>\n" );
document.write( "(2*2*2)/(5*5*5)=8/125<BR>\n" );
document.write( "so, 2/5 to the third power is 8/125 </SPAN>\n" );
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