document.write( "Question 761496: solve y=x^2-3 and 4x-y=6 \n" ); document.write( "
Algebra.Com's Answer #463257 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "For this y=x^2-3 and 4x-y=6 let's substitute as follows:
\n" ); document.write( "4x-x^2+3=6
\n" ); document.write( "This can be rewritten as:
\n" ); document.write( "-x^2+4x+3=6
\n" ); document.write( "Subtract 6:
\n" ); document.write( "-x^2+4x-3=0
\n" ); document.write( "Pull out the negative:
\n" ); document.write( "-1(x^2-4x+3)=0
\n" ); document.write( "Now we can factor this to be:
\n" ); document.write( "-1(x-3)(x-1)=0
\n" ); document.write( "Solve for x:
\n" ); document.write( "x=3
\n" ); document.write( "x=1
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "
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