document.write( "Question 761442: The solution(s) of the equation
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document.write( "2cos^2 x tan x=tan x, over the interval [0,2π)
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document.write( "is (are)? \r
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document.write( "Can you please explain to me how you got the answer?\r
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document.write( "(a) x=0
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document.write( "(b) 𝑥=0,𝜋
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document.write( "(c) 𝑥=0,𝜋4,3𝜋4,𝜋,5𝜋4
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document.write( "(d) 𝑥=0,𝜋4,3𝜋4,𝜋,5𝜋4,7𝜋4
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document.write( "(e) None of the above.
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Algebra.Com's Answer #463241 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! 2cos^2xtanx = tanx \n" ); document.write( "2cos^2xtanx - tanx = 0 \n" ); document.write( "tanx(2cos^2x - 1) = 0 \n" ); document.write( "tanx = 0 \n" ); document.write( " x = 0, pi, 2pi. \n" ); document.write( "2cos^x - 1 = 0 \n" ); document.write( " 2cos^2x = 1 \n" ); document.write( " cos^2x = 1/2 \n" ); document.write( " cosx = 1/sqrt2 \n" ); document.write( " x = pi/4, 7pi/4\r \n" ); document.write( "\n" ); document.write( "[0,pi/4,pi,7pi/4 and 2pi] \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |