document.write( "Question 65636: hello, please can you help me solve this. √2x+1=3 I got confused,
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Algebra.Com's Answer #46324 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Is it:
\n" ); document.write( "1) \"sqrt%282x%2B1%29+=+3\" or:
\n" ); document.write( "2) \"sqrt%282x%29+%2B+1+=+3\"\r
\n" ); document.write( "\n" ); document.write( "If it's equation 1), then:
\n" ); document.write( "\"sqrt%282x%2B1%29+=+3\" Square both sides.
\n" ); document.write( "\"2x%2B1+=+9\" Now subtract 1 from both sides.
\n" ); document.write( "\"2x+=+8\" Finally, divide both sides by 2.
\n" ); document.write( "\"x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "If it's equation 2), then:
\n" ); document.write( "\"sqrt%282x%29%2B1+=+3\" Subtract 1 from both sides.
\n" ); document.write( "\"sqrt%282x%29+=+2\" Now square both sides.
\n" ); document.write( "\"2x+=+4\" Finally, divide both sides by 2.
\n" ); document.write( "\"x+=+2\"
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