document.write( "Question 761466: It takes a rowing crew 1 hour and 30 minutes longer to go 12 miles up a river than to return. Find the speed of the rowing crew in still water if the speed of the current is 2 mph.
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document.write( "I set the problem up ( s= speed and t= time)
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document.write( "Going up river: 12= (s+ 2)t
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document.write( "I then know that t= 12/(s+2)
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document.write( "Going down river: 12= (s-2)(t+1.5)\r
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document.write( "So making the substitution for t:\r
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document.write( "Going down river 12=(s-2)((12/(s+2)) + 1.5)\r
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document.write( "But this is where I run into problems. How do I solve this algebra problem?\r
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document.write( "Thanks\r
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Algebra.Com's Answer #463239 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Let r = speed in still water. You do not know time but you can create expressions for both directions each.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "WAY___________rate_____________time____________distance \n" ); document.write( "Up____________r-2______________12/(r-2)_________12 \n" ); document.write( "Down__________r+2______________12/(r+2)_________12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Upstream was 3/2 hour MORE than downstream: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply left and right by the LCD, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |