document.write( "Question 761466: It takes a rowing crew 1 hour and 30 minutes longer to go 12 miles up a river than to return. Find the speed of the rowing crew in still water if the speed of the current is 2 mph.
\n" ); document.write( "I set the problem up ( s= speed and t= time)
\n" ); document.write( "Going up river: 12= (s+ 2)t
\n" ); document.write( "I then know that t= 12/(s+2)
\n" ); document.write( "Going down river: 12= (s-2)(t+1.5)\r
\n" ); document.write( "\n" ); document.write( "So making the substitution for t:\r
\n" ); document.write( "\n" ); document.write( "Going down river 12=(s-2)((12/(s+2)) + 1.5)\r
\n" ); document.write( "\n" ); document.write( "But this is where I run into problems. How do I solve this algebra problem?\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
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Algebra.Com's Answer #463239 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Let r = speed in still water. You do not know time but you can create expressions for both directions each.\r
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\n" ); document.write( "\n" ); document.write( "WAY___________rate_____________time____________distance
\n" ); document.write( "Up____________r-2______________12/(r-2)_________12
\n" ); document.write( "Down__________r+2______________12/(r+2)_________12\r
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\n" ); document.write( "\n" ); document.write( "Upstream was 3/2 hour MORE than downstream:
\n" ); document.write( "\"highlight%2812%2F%28r-2%29=12%2F%28r%2B2%29%2B3%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply left and right by the LCD, \"2%28r-2%29%28r%2B2%29\" and simplifying,
\n" ); document.write( "\"24%28r%2B2%29=24%28r-2%29%2B3%28r%5E2-4%29\"
\n" ); document.write( ".
\n" ); document.write( "\"48=-48%2B3r%5E2-12\"
\n" ); document.write( "\"96%2B12=3r%5E2\"
\n" ); document.write( "\"3r%5E2=108\"
\n" ); document.write( "\"r%5E2=36\"
\n" ); document.write( "\"highlight%28r=6%29\"
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