document.write( "Question 761451: the distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 63 feet in 8 seconds, how farr will it have fallen by the end of 10 seconds? ( leave the variation constant in fraction form or round to at least 2 decimal places. Round your final answer to the nearest foot.) \n" ); document.write( "
Algebra.Com's Answer #463232 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Let d = distance fallen in feet and
\n" ); document.write( "Let t = fall time in seconds and
\n" ); document.write( "Let c = constant of direct proportionality in feet per seconds squared.
\n" ); document.write( "The formula to use is
\n" ); document.write( "(1) d = c*t^2
\n" ); document.write( "Where we are given
\n" ); document.write( "(2) 63 = c*8^2 or
\n" ); document.write( "(3) c = 63/64
\n" ); document.write( "Then in 10 seconds the distance is given by
\n" ); document.write( "(4) d = 63/64*(10)^2 or
\n" ); document.write( "(5) d = 6300/64 or
\n" ); document.write( "(6) d = 98.4375
\n" ); document.write( "Answer: the constant of variation is 63/64 and the distance dropped in ten seconds is 98 feet.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );