document.write( "Question 761352: A train travelled from Town A to Town B at a uniform speed. If the speed had been increased by 18m.p.h, the time taken for the journey would have been 3 hours less. If the speed had been reduced by 9m.p.h, the time taken for the jounry would have been 3 hours more. Find the speed of the train and the distance between Town A and Town B.\r
\n" );
document.write( "\n" );
document.write( "PLEASE HELP ME!!!!
\n" );
document.write( "thanks \n" );
document.write( "
Algebra.Com's Answer #463187 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let r=rate (speed) of the train \n" ); document.write( "And let d=distance between the two towns \n" ); document.write( "And t=time required for the initial trip \n" ); document.write( "(r+18=speed increased by 18mph) \n" ); document.write( "(r-9=speed reduced by 9mph) \n" ); document.write( "Now we know the following: \n" ); document.write( "d=rt----------------------------eq1 \n" ); document.write( "d=(r+18)(t-3)-------------------eq2 \n" ); document.write( "d=(r-9)(t+3)--------------------eq3 \n" ); document.write( "Looking at eq2 and 3, we see that: \n" ); document.write( "(r+18)(t-3)=(r-9)(t+3) expand each side using FOIL \n" ); document.write( "rt-3r+18t-54=rt+3r-9t-27 collect like terms \n" ); document.write( "-6r+27t=27----------------------eq1b \n" ); document.write( "Looking at eq1 and 2, we see that: \n" ); document.write( "rt=(r+18)(t-3) \n" ); document.write( "rt=rt-3r+18t-54 collect like terms \n" ); document.write( "-3r+18t=54----eq2b \n" ); document.write( "multiply eq2b by 2 and subtract eq1b from it and we get: \n" ); document.write( " (-6r+36t=108) \n" ); document.write( "-(-6r+27t=27) \n" ); document.write( "9t=81 \n" ); document.write( "t=9 hrs---- time needed for the initial trip \n" ); document.write( "substitute t=9 into eq2b and we get \n" ); document.write( "-3r+18*9=54 \n" ); document.write( "-3r=-108 \n" ); document.write( "r=36 mph-----initial speed of the trail \n" ); document.write( "substitute r=36 mph and t=9 hr into eq1 and we get: \n" ); document.write( "d=324 mi distance between the two towns \n" ); document.write( "CK \n" ); document.write( "324=(36+18)(9-3) \n" ); document.write( "324=324 \n" ); document.write( "and \n" ); document.write( "324=(36-9)(9+3) \n" ); document.write( "324=324 \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |