document.write( "Question 761352: A train travelled from Town A to Town B at a uniform speed. If the speed had been increased by 18m.p.h, the time taken for the journey would have been 3 hours less. If the speed had been reduced by 9m.p.h, the time taken for the jounry would have been 3 hours more. Find the speed of the train and the distance between Town A and Town B.\r
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\n" ); document.write( "thanks
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Algebra.Com's Answer #463187 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=rate (speed) of the train
\n" ); document.write( "And let d=distance between the two towns
\n" ); document.write( "And t=time required for the initial trip
\n" ); document.write( "(r+18=speed increased by 18mph)
\n" ); document.write( "(r-9=speed reduced by 9mph)
\n" ); document.write( "Now we know the following:
\n" ); document.write( "d=rt----------------------------eq1
\n" ); document.write( "d=(r+18)(t-3)-------------------eq2
\n" ); document.write( "d=(r-9)(t+3)--------------------eq3
\n" ); document.write( "Looking at eq2 and 3, we see that:
\n" ); document.write( "(r+18)(t-3)=(r-9)(t+3) expand each side using FOIL
\n" ); document.write( "rt-3r+18t-54=rt+3r-9t-27 collect like terms
\n" ); document.write( "-6r+27t=27----------------------eq1b
\n" ); document.write( "Looking at eq1 and 2, we see that:
\n" ); document.write( "rt=(r+18)(t-3)
\n" ); document.write( "rt=rt-3r+18t-54 collect like terms
\n" ); document.write( "-3r+18t=54----eq2b
\n" ); document.write( "multiply eq2b by 2 and subtract eq1b from it and we get:
\n" ); document.write( " (-6r+36t=108)
\n" ); document.write( "-(-6r+27t=27)
\n" ); document.write( "9t=81
\n" ); document.write( "t=9 hrs---- time needed for the initial trip
\n" ); document.write( "substitute t=9 into eq2b and we get
\n" ); document.write( "-3r+18*9=54
\n" ); document.write( "-3r=-108
\n" ); document.write( "r=36 mph-----initial speed of the trail
\n" ); document.write( "substitute r=36 mph and t=9 hr into eq1 and we get:
\n" ); document.write( "d=324 mi distance between the two towns
\n" ); document.write( "CK
\n" ); document.write( "324=(36+18)(9-3)
\n" ); document.write( "324=324
\n" ); document.write( "and
\n" ); document.write( "324=(36-9)(9+3)
\n" ); document.write( "324=324
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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