document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761344>Question 761344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 3 consecutive numbers. When the product of these is divided by each of them in turn, the sum of quotients will be 74. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463185 by </B><A HREF=/tutors/aboutme.mpl?userid=pbdesai><B>pbdesai(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pbdesai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Answer is number-4,5 and 6.<BR>\n" );
document.write( "Solution-abc/a + abc/b + abc/c = 74<BR>\n" );
document.write( "bc+ac+ab= 74<BR>\n" );
document.write( "b(b+1) + (b-1)(b+1) + (b-1)b= 74<BR>\n" );
document.write( "bb +bb+ bb -1= 74<BR>\n" );
document.write( "3bb= 75<BR>\n" );
document.write( "bb = 25<BR>\n" );
document.write( "b= 5. </SPAN>\n" );
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