document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761298>Question 761298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 2:00 pm a runner heads north on a highway jogging at 10 mph. At 2:30 pm a driver heads north on the same highway to pick up the runner. If the car travels at 55 mph how long will it take the driver to catch the runner? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463172 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 2:00 pm a runner heads north on a highway jogging at 10 mph. At 2:30 pm a driver heads north on the same highway to pick up the runner. If the car travels at 55 mph how long will it take the driver to catch the runner?\r<BR>\n" );
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document.write( "At 2:30 the distance between the car and the runner is 5 miles (since the runner covers 10 miles in a hour, or 5 miles  in 30 minutes). The car has to cover this additional distance to catch the runner.\r<BR>\n" );
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document.write( "Let us say the car catches up after x min\r<BR>\n" );
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document.write( "In x min the runner would have run <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10+%2A+x+%2F+60 ALIGN=MIDDLE  ALT=\"10+%2A+x+%2F+60\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles\r<BR>\n" );
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document.write( "in x min the car would have covered <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=55+%2A+x+%2F+60 ALIGN=MIDDLE  ALT=\"55+%2A+x+%2F+60\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles\r<BR>\n" );
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document.write( "The car has to cover whatever the runner has run in x min, plus the head start of 5 miles that the runner had.\r<BR>\n" );
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document.write( "So,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=55+%2A+x+%2F+60 ALIGN=MIDDLE  ALT=\"55+%2A+x+%2F+60\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10+%2A+x+%2F+60 ALIGN=MIDDLE  ALT=\"10+%2A+x+%2F+60\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5 ALIGN=MIDDLE  ALT=\"5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Multiplying both sides by 60\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=55+%2A+x+=+10+%2A+x+%2B+300+ ALIGN=MIDDLE  ALT=\"55+%2A+x+=+10+%2A+x+%2B+300+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Simplifying\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=45+%2A+x+=+300+ ALIGN=MIDDLE  ALT=\"45+%2A+x+=+300+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Dividing both sides by 45\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+300+%2F+45+=+6.667 ALIGN=MIDDLE  ALT=\"x+=+300+%2F+45+=+6.667\"   DISABLED_style= \"max-width:90%; height:auto;\" > min\r<BR>\n" );
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document.write( "Car will catch up with the runner in 6.667 min\r<BR>\n" );
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document.write( ":)<BR>\n" );
document.write( " </SPAN>\n" );
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