document.write( "Question 760727: A can walk from p to q and back in 20 minutes, whereas b can walk from q to p and back in 30 minutes if a and b start towards each other from p and q respectively at 8:am when will they meet? \n" ); document.write( "
Algebra.Com's Answer #463134 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A can walk from p to q and back in 20 minutes, whereas b can walk from \n" ); document.write( " q to p and back in 30 minutes \ \n" ); document.write( "if a and b start towards each other from p and q respectively at 8:am \n" ); document.write( " when will they meet? \n" ); document.write( ": \n" ); document.write( "Let d = one way distance from p to q \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let t = walking time when they meet \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = time * speed \n" ); document.write( ": \n" ); document.write( "A's dist + B's dist = one way dist (d) \n" ); document.write( "t* \n" ); document.write( "multiply by 30 to get rid of the denominators, resulting in \n" ); document.write( "3td + 2td = 30d \n" ); document.write( "divide thru by d \n" ); document.write( "3t + 2t = 30 \n" ); document.write( "5t = 30 \n" ); document.write( "t = 30/5 \n" ); document.write( "t = 6 min \n" ); document.write( ": \n" ); document.write( "They will meet a 8:06 \n" ); document.write( " \n" ); document.write( " |