document.write( "Question 760727: A can walk from p to q and back in 20 minutes, whereas b can walk from q to p and back in 30 minutes if a and b start towards each other from p and q respectively at 8:am when will they meet? \n" ); document.write( "
Algebra.Com's Answer #463134 by ankor@dixie-net.com(22740)\"\" \"About 
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A can walk from p to q and back in 20 minutes, whereas b can walk from
\n" ); document.write( " q to p and back in 30 minutes \
\n" ); document.write( "if a and b start towards each other from p and q respectively at 8:am
\n" ); document.write( " when will they meet?
\n" ); document.write( ":
\n" ); document.write( "Let d = one way distance from p to q
\n" ); document.write( "then
\n" ); document.write( "\"d%2F10\" = A's speed
\n" ); document.write( "and
\n" ); document.write( "\"d%2F15\" = B's speed
\n" ); document.write( ":
\n" ); document.write( "Let t = walking time when they meet
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\n" ); document.write( "Write a distance equation; dist = time * speed
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\n" ); document.write( "A's dist + B's dist = one way dist (d)
\n" ); document.write( "t*\"d%2F10\" + t\"d%2F15\" = d
\n" ); document.write( "multiply by 30 to get rid of the denominators, resulting in
\n" ); document.write( "3td + 2td = 30d
\n" ); document.write( "divide thru by d
\n" ); document.write( "3t + 2t = 30
\n" ); document.write( "5t = 30
\n" ); document.write( "t = 30/5
\n" ); document.write( "t = 6 min
\n" ); document.write( ":
\n" ); document.write( "They will meet a 8:06
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