document.write( "Question 761179: a flat circular plate of copper has a radius of 0.243m and a mass of 62kg. what is the thickness of the plate?
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Algebra.Com's Answer #463086 by josgarithmetic(39617)\"\" \"About 
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While trying to think how to analyze this, no way seems possible without using the density of copper. \r
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\n" ); document.write( "\n" ); document.write( "Use 8.96 grams/cm^3 for copper.\r
\n" ); document.write( "\n" ); document.write( "This density is \"highlight%28kg%2Fm%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "That conversion is to let us use units of only kilograms and meters, or cubic meters.\r
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\n" ); document.write( "\n" ); document.write( "Let h = depth of the disc.
\n" ); document.write( "Volume of the disc is \"h%2Api%2A%280.243%29%5E2\" \"m%5E3\" .
\n" ); document.write( "This volume, based on the mass and density of the copper must be:
\n" ); document.write( "Volume is \"62%2A%281%2F8960%29\" m^3\r
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\n" ); document.write( "\n" ); document.write( "Those two volumes must be equal.
\n" ); document.write( "\"highlight%28h%2Api%2A%280.243%29%5E2=62%2F8960%29\"
\n" ); document.write( "And of course you just solve for h.
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