document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=761125>Question 761125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is one third the length. The perimeter is 80 yards. Find the width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463054 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = x<BR>\n" );
document.write( "Width = x/3<BR>\n" );
document.write( "Perimeter = 2*length + 2*width<BR>\n" );
document.write( "      80 = 2(x) + 2(x/3)<BR>\n" );
document.write( "      80 = 2x + 2x/3<BR>\n" );
document.write( "Common denominator = 3<BR>\n" );
document.write( "      240 = 6x + 2x<BR>\n" );
document.write( "        8x = 240<BR>\n" );
document.write( "         x = 30<BR>\n" );
document.write( "Therefore the width - x/3 = 30/3 = 10 units<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );