document.write( "Question 761054: arith metic progression... please sir solve this question 9years and 4months =28/3 how? \n" ); document.write( "
Algebra.Com's Answer #462997 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You should explain your question more thoroughly. This appears unrelated to arithmetic progressions.\r
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\n" ); document.write( "\n" ); document.write( "You asked how 9 years and 4 months is \"28%2F3\". Starting from the mixed unitted number, you could change all into the number of months.\r
\n" ); document.write( "\n" ); document.write( "9 years is \"9%2A12=111\" months.
\n" ); document.write( "4 more months gives 115 months.\r
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\n" ); document.write( "\n" ); document.write( "You suggest a denominator of 12 from the mixed units and a denominator of 3 is shown on your right-side member number. Four months is \"%281%2F3%29\" of a year. If 9 years were cut into denominations of 3 equal parts, then \"9%2A3=27\".
\n" ); document.write( "One more denomination would be 28 of these denominations. Now, \"28%2F3=9%261%2F3\".
\n" ); document.write( "That must be what you are looking for.
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