document.write( "Question 760995: A farmer needs to build a fence with 2 equal size pens to separate the sheep and pigs. The farmer will build a rectangular outer fence plus a dividing fence down the middle parallel to two sides. If she has a total of 200 feet of fencing, find the dimensions that will enclose the maximum total area. \n" ); document.write( "
Algebra.Com's Answer #462981 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! x for length of the whole area, and y for the width of the whole area. Choose y longer than x, and so take the divider parallel to x. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Accounting for fencing material, \n" ); document.write( "Accounting for area, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter equation gives \n" ); document.write( " \n" ); document.write( "Substitute into area equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A looks like a quadratic equation as a function, and indicates a parabola with a maximum ( openings downward). Finding the zeros is very easy, only requiring back one step in deriving A(x). The maximum A for AREA will occur directly in the middle of the two zeros of A(x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ZEROS of A: \n" ); document.write( " \n" ); document.write( "Either x=0 \n" ); document.write( "OR \n" ); document.write( "100-(3/2)x=0 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Maximum Area occurs at \n" ); document.write( "\n" ); document.write( "To find y, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------More about the area----------- \n" ); document.write( "This area maximum is: \n" ); document.write( "A(100/3)=100(100/3)-(3/2)(100/3)^2 \n" ); document.write( "A=10000/3-(3/2)*10000/9 \n" ); document.write( "A=1000/3-3*10000/18 \n" ); document.write( "A=6*10000/18-3*10000/18 \n" ); document.write( "A=3*10000/(3*6)=10000/6 \n" ); document.write( "A=1667 square feet \n" ); document.write( " |