document.write( "Question 760995: A farmer needs to build a fence with 2 equal size pens to separate the sheep and pigs. The farmer will build a rectangular outer fence plus a dividing fence down the middle parallel to two sides. If she has a total of 200 feet of fencing, find the dimensions that will enclose the maximum total area. \n" ); document.write( "
Algebra.Com's Answer #462981 by josgarithmetic(39617)\"\" \"About 
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x for length of the whole area, and y for the width of the whole area. Choose y longer than x, and so take the divider parallel to x. \r
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\n" ); document.write( "\n" ); document.write( "Accounting for fencing material, \"3x%2B2y=200\".
\n" ); document.write( "Accounting for area, \"A=xy\"\r
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\n" ); document.write( "\n" ); document.write( "Perimeter equation gives \"2y=200-3x\"
\n" ); document.write( "\"y=100-%283%2F2%29x\"
\n" ); document.write( "Substitute into area equation.
\n" ); document.write( "\"A=x%28100-%283%2F2%29x%29\"
\n" ); document.write( "\"A=100x-%283%2F2%29x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "A looks like a quadratic equation as a function, and indicates a parabola with a maximum ( openings downward). Finding the zeros is very easy, only requiring back one step in deriving A(x). The maximum A for AREA will occur directly in the middle of the two zeros of A(x).\r
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\n" ); document.write( "\n" ); document.write( "ZEROS of A:
\n" ); document.write( "\"0=x%28100-%283%2F2%29x%29\"
\n" ); document.write( "Either x=0
\n" ); document.write( "OR
\n" ); document.write( "100-(3/2)x=0
\n" ); document.write( "\"100=3x%2F2\"
\n" ); document.write( "\"100%2A2%2F3=x\"
\n" ); document.write( "\"x=200%2F3\"
\n" ); document.write( "Maximum Area occurs at \"%280%2B200%2F3%29%2F2=highlight%28100%2F3=x%29\"\r
\n" ); document.write( "\n" ); document.write( "To find y,
\n" ); document.write( "\"y=100-%283%2F2%29x\"
\n" ); document.write( "\"y=100-%283%2F2%29%28100%2F3%29=100-3%2A100%2F%282%2A3%29=100-100%2F2\"
\n" ); document.write( "\"highlight%28y=50%29\"\r
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\n" ); document.write( "\n" ); document.write( "----------------------------------More about the area-----------
\n" ); document.write( "This area maximum is:
\n" ); document.write( "A(100/3)=100(100/3)-(3/2)(100/3)^2
\n" ); document.write( "A=10000/3-(3/2)*10000/9
\n" ); document.write( "A=1000/3-3*10000/18
\n" ); document.write( "A=6*10000/18-3*10000/18
\n" ); document.write( "A=3*10000/(3*6)=10000/6
\n" ); document.write( "A=1667 square feet
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