document.write( "Question 760979: in a collection of nickels and quarters, there are two more nickels than quarters. how many of each coin are there if the collection is worth $3.40? \n" ); document.write( "
Algebra.Com's Answer #462964 by 2897696(96)\"\" \"About 
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The way I would solve this is by making a table like this
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\n" ); document.write( "type (of coin)!V(value of coin)!A(amount of coin)!T(total of coin)
\n" ); document.write( "--------------!----------------!-----------------!----------------
\n" ); document.write( "quarters !0.25 !x(unknown) !0.25x(multiply V&A to get T)
\n" ); document.write( "--------------!----------------!-----------------!----------------
\n" ); document.write( "nickel !0.05 !x+2(two more !0.05(x+2)
\n" ); document.write( " nickels than
\n" ); document.write( " quarters)
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\n" ); document.write( "\n" ); document.write( "From this chart we can make an equation (always from the (T)total section)
\n" ); document.write( "0.25x+0.05(x+2)=3.40 *the amount of coins are equal to 3.40 since the amount of nickels and quarter equal 3.40.
\n" ); document.write( "After making the equation solve for x, which will give you the amount of quarters......
\n" ); document.write( "BUT, you are not done yet, because you must also find how many nickels.
\n" ); document.write( "To find the amount of nickels simply use the equation x+2 from the amount (A) column. once you find the answer check with mine, which will be at the bottom of this)\r
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\n" ); document.write( "\n" ); document.write( "Answer: \r
\n" ); document.write( "\n" ); document.write( "quarters:11
\n" ); document.write( "nickels:13 *sorry table is shifted, each column is defined by this !\r
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