document.write( "Question 760992: A train travels 110 km in the same time that a plane covers 385 km. If the speed of the plane is 20 km less than 4 times the speed of the train, find both speeds.\r
\n" ); document.write( "\n" ); document.write( "I know this is a distance times time gets rate formula problem where the blank has to be filled in be elimination or substitution. All I can figure out is the abbrevations that I want to use for train (t) and plane (p) and the numbers that go with them. t110 and p385. that's all I've come with. \n" ); document.write( "
Algebra.Com's Answer #462962 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A train travels 110 km in the same time that a plane covers 385 km. If the speed of the plane is 20 km less than 4 times the speed of the train, find both speeds.
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\n" ); document.write( "train DATA:
\n" ); document.write( "distance = 110 km ; time = x hrs ; ; rate = 110/x hrs
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\n" ); document.write( "plane DATA:
\n" ); document.write( "distance = 385 km ; time = x hrs ; rate = 385/x hrs\r
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\n" ); document.write( "Equation:
\n" ); document.write( "plane rate = 4*train rate - 20
\n" ); document.write( "---
\n" ); document.write( "(385/x) = 4(110/x) - 20
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\n" ); document.write( "385 = 4(110) - 20x
\n" ); document.write( "20x = 440-385
\n" ); document.write( "20x = 55
\n" ); document.write( "x = 11/4 hrs
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\n" ); document.write( "car rate = 110/(11/4) = 440/11 = 40 km/hr
\n" ); document.write( "---
\n" ); document.write( "plane rate = 385/(11/4) = 140 km/hr
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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