document.write( "Question 760930: the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s. At what time is the bullet 5280 ft above the ground? \n" ); document.write( "
Algebra.Com's Answer #462940 by Alan3354(69443)\"\" \"About 
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the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s.
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\n" ); document.write( "h(t)=-16t^2+Vot+ho
\n" ); document.write( "h(t)=-16t^2 + 2200t + 20
\n" ); document.write( "Sub 40 for t to find h(40)
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\n" ); document.write( "At what time is the bullet 5280 ft above the ground?
\n" ); document.write( "h(t)=-16t^2 + 2200t + 20 = 5280
\n" ); document.write( "Solve for t
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