document.write( "Question 760930: the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s. At what time is the bullet 5280 ft above the ground? \n" ); document.write( "
Algebra.Com's Answer #462940 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s. \n" ); document.write( "---------- \n" ); document.write( "h(t)=-16t^2+Vot+ho \n" ); document.write( "h(t)=-16t^2 + 2200t + 20 \n" ); document.write( "Sub 40 for t to find h(40) \n" ); document.write( "================================ \n" ); document.write( "At what time is the bullet 5280 ft above the ground? \n" ); document.write( "h(t)=-16t^2 + 2200t + 20 = 5280 \n" ); document.write( "Solve for t \n" ); document.write( " \n" ); document.write( " |