document.write( "Question 760889: Jacksonville and Tampa are 210 miles apart, George leaves Tampa at the same time that Joshua leaves Jacksonville. They drive towards each other and meet in 2 hours. What was each person's speed if George travels 5 mph faster than Joshua? \n" ); document.write( "

Algebra.Com's Answer #462924 by josmiceli(19441) $\"\"$ $\"About$

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Think of one driver as standing still and
\n" ); document.write( "the other one moving at the sum of their speeds
\n" ); document.write( "-----------------
\n" ); document.write( "Let $\"+s+\"$ = Joshua's speed in mi/hr
\n" ); document.write( " $\"+s+%2B+5+\"$ = George's speed in mi/hr
\n" ); document.write( "--------------------------------
\n" ); document.write( " $\"+210+=+%28+s+%2B+s+%2B+5+%29%2A2+\"$
\n" ); document.write( " $\"+210+=+%28+2s+%2B+5+%29%2A2+\"$
\n" ); document.write( " $\"+210+=+4s+%2B+10+\"$
\n" ); document.write( " $\"+4s+=+200+\"$
\n" ); document.write( " $\"+s+=+50+\"$
\n" ); document.write( " $\"+s+%2B+5+=+55+\"$
\n" ); document.write( " Joshua's speed is 50 mi/hr
\n" ); document.write( "George's speed is 55 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "Joshua's equation:
\n" ); document.write( " $\"+d%5B1%5D+=+50%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+100+\"$ mi
\n" ); document.write( "George's equation:
\n" ); document.write( " $\"+d%5B2%5D+=+55%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+110+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+100+%2B+110+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=210+\"$
\n" ); document.write( "OK\r
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