document.write( "Question 760908: I need help with Graphing lines, I have 2x-4y=12
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document.write( "I have a chart that has X -2, -1,0, 1, 2, and Y is blank. I don't understand how to answer it or what to do. \n" );
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Algebra.Com's Answer #462920 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! I need help with Graphing lines, I have 2x-4y=12 \n" ); document.write( "*** \n" ); document.write( "The first step is to rewrite equation in terms of y and in standard form for a straight line. \n" ); document.write( "2x-4y=12 \n" ); document.write( "4y=2x-12 \n" ); document.write( "y=x/2-3 \n" ); document.write( "This is an equation of a straight line whose standard form is: y=mx+b. m=slope, b=y-intercept \n" ); document.write( "From here, you can plug in several different values of x to get points for the graph. \n" ); document.write( "A better and more efficient way is find the y-intercept which=3 in this case, and use the slope=1/2 in this case to get a 2nd point. From the y-intercept, move 2 units to the right and one unit up to get the 2nd point. Run the line thru these two points for the graph. Plug in an x-value as a check to see if it falls on the line as it should. \n" ); document.write( "note: slope=rise/run=∆y/∆x\r \n" ); document.write( "\n" ); document.write( "see graph below as a visual check: \n" ); document.write( " |