document.write( "Question 760908: I need help with Graphing lines, I have 2x-4y=12
\n" ); document.write( "I have a chart that has X -2, -1,0, 1, 2, and Y is blank. I don't understand how to answer it or what to do.
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Algebra.Com's Answer #462920 by lwsshak3(11628)\"\" \"About 
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I need help with Graphing lines, I have 2x-4y=12
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\n" ); document.write( "The first step is to rewrite equation in terms of y and in standard form for a straight line.
\n" ); document.write( "2x-4y=12
\n" ); document.write( "4y=2x-12
\n" ); document.write( "y=x/2-3
\n" ); document.write( "This is an equation of a straight line whose standard form is: y=mx+b. m=slope, b=y-intercept
\n" ); document.write( "From here, you can plug in several different values of x to get points for the graph.
\n" ); document.write( "A better and more efficient way is find the y-intercept which=3 in this case, and use the slope=1/2 in this case to get a 2nd point. From the y-intercept, move 2 units to the right and one unit up to get the 2nd point. Run the line thru these two points for the graph. Plug in an x-value as a check to see if it falls on the line as it should.
\n" ); document.write( "note: slope=rise/run=∆y/∆x\r
\n" ); document.write( "\n" ); document.write( "see graph below as a visual check:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%2F2-3%29+\"
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