document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=331978>Question 331978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question: An angle measures 15° more than twice its supplement. Find the measure of the supplement. What is the measure of the supplement angle?\r<BR>\n" );
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document.write( "I'm homeschooled online so I don't really have a teacher that can help me when I don't understand a problem unless I stay 30 minutes or more on the phone waiting for someone from my online school to answer and not even being able to help me out, so I would really appreciate it if you could please help me out with this problem because I've tried to solve it so many times, but I just can't work it out. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462914 by </B><A HREF=/tutors/aboutme.mpl?userid=vosotroslovely><B>vosotroslovely(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vosotroslovely><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x = the supplement and the angle is 15° more than twice its supplement, then the angle is 2x + 15.\r<BR>\n" );
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document.write( "x + 2x+15 = 180<BR>\n" );
document.write( "3x + 15 = 180<BR>\n" );
document.write( "3x = 165<BR>\n" );
document.write( "x = 55° <= supplement<BR>\n" );
document.write( "2x+15 = 2(55) + 15 = 125° <= angle\r<BR>\n" );
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document.write( "The supplement is 55°. </SPAN>\n" );
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