document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760844>Question 760844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the lateral area and the surface area of a right cylinder that is 10 feet high and has a base with a radius of 5 feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462907 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lateral area  = Circumference * height<BR>\n" );
document.write( "                 = ( Pi * diam) * height<BR>\n" );
document.write( "                = 314.16ft^2<BR>\n" );
document.write( "Surface Area = 2 Pi r^2 + 2 Pi r h<BR>\n" );
document.write( "               2 * Pi * 5^2 + 2 * Pi * 5 * 10<BR>\n" );
document.write( "             =    157.08 + 314.16<BR>\n" );
document.write( "             =        471.24ft^2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );