document.write( "Question 8448: Can u please help me with this problem.....\r
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\n" ); document.write( "\n" ); document.write( "x:4x < x-9\r
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\n" ); document.write( "\n" ); document.write( "a. x > 4
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\n" ); document.write( "c. x < -9
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Algebra.Com's Answer #4629 by drglass(89)\"\" \"About 
You can put this solution on YOUR website!
First, subtract x from both sides:\r
\n" ); document.write( "\n" ); document.write( "4x - x < x - 9 - x
\n" ); document.write( "3x < -9\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 3 to get\r
\n" ); document.write( "\n" ); document.write( "3x/3 < -9/3
\n" ); document.write( "x < -3
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